Consider x^2-9. Rewrite x^2-9 as x^2-3^2. The difference of squares can be factored using the rule: a^2-b^2=left(a-b ight)left(a+b ight).

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2x2-18=0 Two solutions were found : x = 3 x = -3 Step by step solution : Step 1 :Equation at the over of step 1 : 2x2 - 18 = 0 Step 2 : Step 3 :Pulling out lượt thích terms : 3.1 Pull ...
2x2-20x=7 Two solutions were found : x =(20-√456)/4=5-1/2√ 114 = -0.339 x =(20+√456)/4=5+1/2√ 114 = 10.339 Rearrange: Rearrange the equation by subtracting what is to lớn the right of the equal ...
32x2-18=0 Two solutions were found : x = ba phần tư = 0.750 x = -3/4 = -0.750 Step by step solution : Step 1 :Equation at the end of step 1 : 25x2 - 18 = 0 Step 2 : Step 3 :Pulling out like ...
2x2-128=0 Two solutions were found : x = 8 x = -8 Step by step solution : Step 1 :Equation at the over of step 1 : 2x2 - 128 = 0 Step 2 : Step 3 :Pulling out lượt thích terms : 3.1 Pull ...
2x2-18x=0 Two solutions were found : x = 9 x = 0 Step by step solution : Step 1 :Equation at the over of step 1 : 2x2 - 18x = 0 Step 2 : Step 3 :Pulling out like terms : 3.1 Pull ...
12x2-8=0 Two solutions were found : x = ±√ 0.667 = ± 0.81650 Step by step solution : Step 1 :Equation at the kết thúc of step 1 : (22•3x2) - 8 = 0 Step 2 : Step 3 :Pulling out ...
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Consider x^2-9. Rewrite x^2-9 as x^2-3^2. The difference of squares can be factored using the rule: a^2-b^2=left(a-b ight)left(a+b ight).
Quadratic equations like this one, with an x^2 term but no x term, can still be solved using the quadratic formula, frac-b±sqrtb^2-4ac2a, once they are put in standard form: ax^2+bx+c=0.

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This equation is in standard form: ax^2+bx+c=0. Substitute 2 for a, 0 for b, và -18 for c in the quadratic formula, frac-b±sqrtb^2-4ac2a.
left< eginarray l l 2 và 3 \ 5 và 4 endarray ight> left< eginarray l l l 2 và 0 và 3 \ -1 & 1 & 5 endarray ight>

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